25 Answered Questions for the topic Line
Finding an equation that is parallel to another equation
What is the equation to the line that is parallel to y=-1/2x-3 and passes through the point (5,2)
Consider the region between the graph of f(x)=x−2 and the x-axis on [2,4]. For the line of rotation given below, use a definite integral to find the volume of the resulting solid.
Around the line x=7 The volume of the solid is___________? PLEASE show work!! STEP BY STEP!!!
Use implicit differentiation to find the slope of the tangent line to the curve defined by xy^3+2xy=60 at the point (5,2)
I would appreciate if all work is shown with detailed steps! Provide the answer to the slope of the tangent line to the curve at the given point is _____.
Picture of a derivative?
How can the limit definition of a derivative be illustrated?
Determine which side of a line a point lies?
I've got a line through points (x1,y1) and (x2, y2). I'd like to see if point (x3, y3) lies to the "left" or "right" of said line. How would I do so?
Find a tangent point on circle?
Given a line with first end point P(x1,y1) another end point is unknown, intersect with a circle that located at origin with radius R at only one point(tangent) T(x2,y2). Anyone know how to get the... more
A graph shows the relationship between the diameter and the circumference of a circle with the point (1, 3.14) shown.
Find three more points that are on the line.
A triangle in space is defined by the points P = (1,1,2), Q = (−1,0,3) and R = (2,1,−1). Find a vector form and the parametric equations for the equation of the line passingthrough P and... more
Perpendicular to the line 3x+5y=-2; y intercept =2
Find an equation
line passing through origin and parallel to Y-axis
What is the Equation of line passing through origin and parallel to Y-axis?
Find equation of a line
A line passes throught the point (1,-4) and has a slope of 8
Find the equation of the line
Find the equation of the line that gies through (- 5, - 4) and is perpendicular to x = - 13. Write in the form y = mx + b.
Equation of a line
Write an equation of the line (2,6) and parallel to y = 2x - 4. Write the equation in the form y = mx + b.
Equation of a line
Write the equation of the line passing through the given points. Write the equation in standard form Ax+By=C. (-4,-2) and (-6,-1)
Finding x and b in the following
Find x so that the given points are collinear. (9, -12) (13, 4) (x, 14) A line with slope of -4 contains the points (2, -8) and (7, b). What is b?
Which equation represents a line which is parallel to the line y-2x=3?
A. y=1/2x-3 B.y=−12x+4 C.y=2x−2 D.y=−2x−4 y=2x−2
Find the point on the line.
Find the point on the line 4x+6y+1=0 which is closest to the point (-1,1)
Find the slope of the tangent line to the curve
Find the slope of the tangent line to the curve (a lemniscate) 2(x2+y2)2= 25(x2-y2) at the point (-3,-1) m=
Find the equations to both line
Find the equations to both lines through the point (2,1) that are tangent to the parabola y=x2+x+4 y= (smaller slope) y=(larger slope)
find the equation of the tangent line
Find the equation of the tangent line to the curve at the given point.\\ y=1+2x-x3, (1,2) y=
estimate the slope of the tangeant line to the curve at P(9,7)
The point P(9,7) lies on the curve y= √x +4. Let Q be the point (x,√x+4) if x is 9.1, the slope of PQ is 0.166206 if x= 9.01, the slope of PQ is 0.16662 if x= 8.9, the slope of PQ is... more
Find the slope of the secant line
The point P(9,7) lies on the curve y=√(x)+4 Let Q be the point (x, (√(x)+4)). A) Find the slope of the secant line PQ for the following values of x. (Answers should be correct to at least 6... more
a balloon was 65 feet to the right of where it was tied and 20 feet above the ground. What could be the slope of the line between the balloon and the point where it was tied?
How do you label points where the line crosses the axes?
I am doing homework and this is the equation: y= -x -4 along with graph to chart it on. We are working on integer linear equations and graphing on charts. If you could help, it would clear some... more