Hi Madison,
Regarding your first 3 points
(9,-12) (13,4)(x,14)
In order for all three points to be collinear they must be on the same line.
Using the first 2 points we can determine the equation of the line
y-y1 = m (x-x1)
where m is the slope and (x1,y1) is one of the given points.
The slope is
m = (y2-y1)/(x2-x1) = ([4-(-12)]/(13-9) = 16/4 = 4
y-4 = 4(x-13)
Let's solve this for y
y-4 = 4x-52
y = 4x-48
Now we need to find the x in the point (x,14)
We can evaluate the equation of the line we determined above for the point and solve for x.
y = 4x-48
14 = 4x-48
62 = 4x
15.5 = x
Now for the second set of points.
Using the point slope form of an equation of a line.
y-(-8) = (-4)(x-2)
y+8 = -4x+8
y = 4x
Evaluation this equation using the point (7,b)
y = 4x
b = (4)(7)
b = 28