Algebra 1 Translations on a coordinate plane

Question

Coordinates of ABC

A (-7,9)

B (7,2)

C (-2,-6)

Translation vector (9,0) Coordinates of A'B'C

( , )

( , )

( , )

Translation vector (0,-12)

Coordinates of A'B'C

( , )

( , )

( , )

Translation vector (3,-8) Coordinates of A'B'C

( , )

( , )

( , )

Translation vector (-7,9) Coordinates of A'B'C

( , )

( , )

( , )

Answer 1

Good morning!

If you would like to see a visual of the translation, go ahead and plot the three coordinates on an X, Y graph. It is a triangle shape with two of the points in the negative X plane (left side of the Y axis).

To translate, you will need to simply add (or subtract if the number is negative) the given vector.

Answer:

To translate A to (9,0), you take each of the coordinates given and add them to (9,0).

A: (-7, 9) translates to (2, 9) because -7 + 9 (x coordinates) is 2, and 9 +0 (Y coordinates) is 0

To translate B to (9,0), you take each of the coordinates given and add them to (9,0).

B: (7, 2) translates to (16, 2) because 7 + 9 (x coordinates) is 16, and 2 +0 (Y coordinates) is 2

To translate C to (9,0), you take each of the coordinates given and add them to (9,0).

C: (2, -6) translates to (11, -6) because 2 + 9 (x coordinates) is 11, and -6 +0 (Y coordinates) is -6

Does this make sense? Try the translation from the original ABC to (0, -12) and see if you can get it. Check back in and let me know what you got, then we can work on the rest!