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12p+15c>360

solve and graph this problem please

 

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It doesn't matter if you solve for the "c"  (y) or "p" (x) intercept, the graph of the solution is the same (or reflected if you label the axis in the opposite way; c=x and p=y).

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Cornelia M. | Math Tutor - Specializing in Algebra and GeometryMath Tutor - Specializing in Algebra and...
5.0 5.0 (839 lesson ratings) (839)
1

There are 2 variables, so you can't 'solve' this equation. However, you can certainly graph it. First, look at like 12x+15y>360. This equation can be simplified by dividing each term by 3. You get 4x+5y>120. Let's pick two points to put on our graph paper that satisfy this equation. If x=0, then y=24. If y=0, then x=30. OK, plot (0,24) and (30,0) on your graph paper and connect the dots with a dotted line since your inequality sign is >. Now, what side to shade? Does the point (0,0) satisfy the equation? No (0 is not greater than 360). OK, so shade the side NOT containing (0,0). Sorry that I can't show the graph to you. Good luck! From, Cornelia M.

Wendy K. | Math Tutor and Mom with a B.S. in Mathematics from UMDMath Tutor and Mom with a B.S. in Mathem...
4.7 4.7 (18 lesson ratings) (18)
0

For the instruction to "solve" the equation, did they specify "solve for p" or "solve for c" ? If so, then that means to first put it in slope-intercept form by using algebra to get the p or the c by itself on the left side of the ">" sign.

Barbara W. | Math Magic EPCOT engineering week presenterMath Magic EPCOT engineering week presen...
4.9 4.9 (185 lesson ratings) (185)
0

In the answer provided by Cornelia M., it is assumed that p=x and c=y.  You would label the x axis "p" and the y axis "c".  Point (0,24) would have p=0 and c=24.  Point (30,0) would have p=30 and c=0.

This is the "solution" to the equation, all points in the shaded area, not including points directly on the dashed line.