Odds are you meant to put parentheses in such as (8x+32)/(x^2-16)
then it's a factoring problem = 8(x+4)/(x+4)(x-4). The (x-4)'s cancel leaving
8/(x-4) where x can be any real number except 4 or -4, as that makes the denominator 0 and the expression undefined. You might miss -4 as disallowed if you look only at the expression after cancelling factors.
However, without the parentheses, the problem is
8x + 32/x^2 -16, with 3 terms, and only 1 in fractional form
You could factor out an 8 to get
8(x + 32/x^2 - 16). That's as simple as it gets. But this way, x=0 is the disallowed value that makes the expression undefined.
but the way it's written you really have 3 terms, 8x, 32/x^2 and -16 all added together, which gives
8x-16 + 32/x^2 (in exponential order) you can factor out 8 to get