Let HD = number of hot dogs
BB = number of buffalo burgers
Profit = 1.5HD + 2BB
240HD + 320BB <= 43,680
BB <= 88
.8HD + 1.25BB <= 150
Solution: Max Profit = $273
HD = 150
BB = 24
Lucas C.
asked 07/19/19A street vendor sells hot dogs and buffalo burgers. A hot dog costs the vendor $0.80 and the buffalo burger costs the vendor $1.25. The hot dog occupies 240 cm3 in space and the buffalo burger occupies 320 cm3. The vendor can only get a maximum of 88 buffalo burgers daily. The vendor spends a maximum of $150 on food per day and has a total of 43 680 cm3 in space to store food. The vendor gets $1.50 in profit per hot dog and $2 in profit per buffalo burger.
Let HD = number of hot dogs
BB = number of buffalo burgers
Profit = 1.5HD + 2BB
240HD + 320BB <= 43,680
BB <= 88
.8HD + 1.25BB <= 150
Solution: Max Profit = $273
HD = 150
BB = 24
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