Raymond B. answered 04/09/22
Math, microeconomics or criminal justice
graph the parabola with axis of symmetry x=0, x intercepts x=9 and -9,
height of the tunnel is 16 meters? or 16 meters from top of the tunnel to an edge of the bottom?
if the former, the y intercept = 16 and the vertex is (0, 16)
the equation is y=a(x-9)(x+9) = a(x^2 -81) where a<0
to find a plug in the point (0,16)
16 =-a81
a =-16/81
the equation is y = (-16/81)(x^2 -81)
or y = (-16/81)x^2 + 16
if the truck is 4 meters wide, graph its x coordinates as -2 and 2, if it drives down the center of the tunnel's road.
then find y(2) = (-16/81)(2^2) +16 = -64/81 + 16 = 15.21 meters is high enough for a 8 meter high truck
but if the truck goes down only a right lane, right of center, graph the x coordinates of the truck as 0 and 4
y(4) = (-16/81)(4^2) + 16 = -256/81 +16 = 12.84 meters also high enough for the 8 meter high truck to pass through.