Roger N. answered 07/29/21
. BE in Civil Engineering . Senior Structural/Civil Engineer
Solution:
The expression for velocity Vx = 5-2t find the acceleration ax in the x direction
ax = dv/dt = d(5-2t)/dt = -2 m/s2 with ax having same direction as Vx
The Magnitude of the force Fx = m ax with Fx having same direction as ax
F= 3kg ( -2 m/s2) = -6 kg.m/s2 = -6N
Tomas C.
Thank you07/30/21