please help me with this problem

Question

Find the equation of the horizontal line that contains the point (7,−8).

Express the equation using either the general form or the​ slope-intercept form of the equation of a line.

Answer 1

A horizontal line (please draw one on a graph) has the same value of y for every value of x. Since the line contains the point (7,-8), the equation is y=-8.

General Form looks like Ax+By+C = 0

y + 8 = 0 [A=0; B=1: C=8]

Slope-intercept form looks like y=mx+b

y = -8 [m=0 (the slope is 0), b=-8 (the y-intercept is (0,-8)]

Answer 2

a horizontal line passes through the y-axis. So the equation of a horizontal line is always y = a number. The point they give us is (7,-8). The y-value of this point is -8 so our equation will be y = -8. If you have any questions don’t hesitate to reach out!

Answer 3

A horizontal line has an equation in the form y = k, where k is a constant.

To pass through (7, -8) y must be -8.

y = -8

Answer 4

Horizontal lines cross through the y-axis (the horizontal axis) of a graph. So the equation of a horizontal line is always y = a number. Since this line needs to go through the point (7,-8), we will have the line y = -8 since the -8 is the y-value of the point given. If you have any questions don’t hesitate to reach out!