If a ball is thrown straight up into the air with an initial velocity of 60 ft/s...?
If a ball is thrown straight up into the air with an initial velocity of 60 ft/s, its height in feet after t seconds is given by y=60t−16t^2. Find the average velocity for the time period beginning when t=1 and lasting:
(i) 0.5 seconds:
(ii) 0.1 seconds:
(iii) 0.01 seconds:
(iv) 0.0001 seconds:
Finally, based on the above results, guess what the instantaneous velocity of the ball is when t=1.