I am happy to explain this to you:
First you should find the amount of energy transferred. This is done by using the heat of fusion:
Q= (mass)(latent heat of fusion)
Lf ice= 333kJ/kg
Lf H2O= 334kJ/kg
so: Qice =.06247kg (333kJ/kg) = 20.8kJ and QH20= .497kg(334kJ/kg)
Now entropy: S= (energy transferrred)/(temperature)
Temperature is measured in kelvin
Sice = 20.8kJ/273.15K = .07kJ/k
SH20 = .586kJ/K
Now for the change in entropy we will take the entropy of water minus the entropy of ice
ΔS= .586kJ/k -.07kJ/K = .516 kJ/K
Thus the entropy increased and is consistent with the physical law that entropy either remains the same or increases!
I hope this helps!