y=a(x+4)^2 +3 is the parabola's equation in vertex form with vertex = maximum point = (-4,3)
to solve for a, the coefficient of the x^2 term, we need one more point on the parabola, plug it in and simplify
use (-2,-1), x=-2, y=-1
-1 = a(-2+4)^2 +3 = 4a +3
a = -4/4 = -1
y = f(x) = -(x+4)^2 +3 is the parabola's equation
to find f^-1(x) switch x and y and solve for the new y
x =-(y+4)^2 + 3
solve for y
3-x = (y+4)^2
take the square root of both sides
y+4 =+ or - sqr(3-x)
y =+ or - sqr(3-x) - 4 is the equation of the inverse relation
f^-1(x) = + sqr(3-x) -4
range is any real value, (-infinity, + infinity)
domain is x<3 or the interval (3, infnity)
It's a rightward opening parabola with vertex (3, -4)