If it is frictionless we only need to determine the work done against gravity =mgh
We can calculate h by using trig h=750 * sin(9.5) = 123.8 meters
Therefore work = 850 * 9.8 * 123.8 = 1.031 Million Joules
With two sig figs it is 1.0 x 10^6 Joules
Pretty G.
asked 10/04/21What is the minimum work needed to push a 850 -kgkg car 750 mm up along a 9.5 ∘∘ incline? Ignore friction.
Express your answer to two significant figures and include the appropriate units.
If it is frictionless we only need to determine the work done against gravity =mgh
We can calculate h by using trig h=750 * sin(9.5) = 123.8 meters
Therefore work = 850 * 9.8 * 123.8 = 1.031 Million Joules
With two sig figs it is 1.0 x 10^6 Joules
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