J.R. S. answered 05/13/21
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
2.0 kg Fe x 1000 g / kg x 1 mol/55.8 g = 35.84 moles Fe
35.84 moles Fe x 13.80 kJ/mol = 494 kJ (answer C)
Maddie D.
asked 05/13/21Calculate the amount of heat needed to melt 2.0 kg of iron at its melting point (1809 K) given that: ΔHfus = 13.80 kJ/mol.
A. 27,600 kJ
B. 25,000kJ
C. 494 kJ
D. 27.6 kJ
J.R. S. answered 05/13/21
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
2.0 kg Fe x 1000 g / kg x 1 mol/55.8 g = 35.84 moles Fe
35.84 moles Fe x 13.80 kJ/mol = 494 kJ (answer C)
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