Point J (-4, -6) and point K (4, 4) are located on the coordinate grid. Which measurement is the closest to the distance between point J and point K in units?

Answer 1

Use the distance formula.

d = sqrt[(x₂ - x₁)² + (y₂ - y₁)²]

d = sqrt[(4 + 4)² + (4 + 6)²]

d = sqrt[8² + 10²]

d = sqrt[64 + 100]

d = sqrt[164]

d = 12.80

Answer 2

sqr164 = about 12.806

It's a 10 by 8 by 12.806 right triangle 4--6 =10, 4--4 = 8 base=8, height=10 hypotenuse = sqr164

10^2 + 8^2 = distance from J to K squared = 164

distance = sqr164 = 12.806, rounded to 3 decimal places

Answer 3

The distance formula is: the square root of [(x2-x1)²+(y2-y1)²]

Therefore, the distance between the two points is:

the square root of [(4-(-4))²)+(4-(-6))²]

which is the square root of (8²)+(10²)

which is the square root of 64+100

which is the square root of 164 or approximately 12.806 units