J.R. S. answered 03/29/21
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
Here is how you do this, without having to contact one of us and book a session.
You have a reaction between the KHP (a monoprotic acid) and barium hydroxide, Ba(OH)2. This is a neutralization reaction which forms a salt (barium potassium phthalate) plus water. We should write the correctly balanced equation before we begin our calculations.
We have the following reaction:
2KHP + Ba(OH)2 ==> Ba(KP)2 + 2H2O
First, we'll figure out how many moles of KHP we have present. The molar mass of KHP is 204.2 g / mole.
Thus, 2.228 g x 1 mol / 204.2 g = 0.01091 moles KHP
Next, using the balanced equation, we'll figure out how many moles of Ba(OH)2 it took to neutralize this amount of KHP:
0.01091 mol KHP x 1 mol Ba(OH)2 / 2 mol KHP = 0.005455 moles Ba(OH)2
Finally, we'll calculate the concentration of the Ba(OH)2 since we know the moles and the volume:
0.005455 mol / 0.02859 L = 0.1908 mol/L = 0.1908 M Ba(OH)2

J.R. S.
03/29/21
Avery B.
You are the best!03/29/21