The normal force is given by mg(cos45) = 693 N
If the box is sliding down with an acceleration of 3 m/s2 we can write
100 (3) = mg(sin45) -f where f is the friction force
Therefore friction force = 693 - 300 = 393 N
Since friction = μ x Normal Force
we get 393 = (μ)(693)
Therefore μ= 0.57