How cold would a 263 calorie drink have to be for all the calories to be burned by the body regulating the temperature?

Question

This is mostly hypothetical, as the actual temperature would probably be lethal to a human, but if a Human burns calories maintaining thermal homeostasis, one could assume that at some point, if the beverage was cold enough, one could burn all the calories within said drink simply by the body heating it up to body temperature.

To give some constants, assume the drink is 16 ounces and contains roughly 263 Calories (kcal). how cold would it have to be for the body to burn all the calories in the drink via the bodies own thermal homeostasis?

I tried doing the maths myself but ended up getting something in the neighborhood of -542° C, which, being under absolute zero, leads me to believe I was either mistaken, or don't know something about the amount of calories needed to lower the temperature of things below freezing.

Answer 1

Dear Andrew G.

Well let's see. 263000 cal / (16 oz * 30g/oz, roughly) ~ 548 cal / g of drink. Assume 37 cal / g sensible heat down to freezing point, and 80 cal / g in freezing or thawing it (disregard effects of solutes). That still leaves 431 cal / g to be made up by heating frozen drink to 0 C; since specific heat of ice ~ 0.5 cal / C, that's -860C you'd have to start at. The point is, that's not feasible.