Hannah R. answered 10/16/25
Stanford biochemistry PhD candidate for Math and Science Tutoring
Let's write a summary.
b = blue eyes. Need 2 copies to have blue eyes.
B = brown eyes. Only need 1 copy to have brown eyes.
The mother has blue eyes, so she must have two copies of the recessive gene. She is bb.
The father has brown eyes, so he has to have at least one copy of the dominant gene. He is B_
The children have a mix of blue and brown eyes, so they are bb and B_.
For a child to have blue eyes, the father would have to pass a copy of the recessive gene down. The father is Bb.
Now we can complete the cross to get the ratio. You can write a punnet square or do a probability calculation.
P(bb) = P(b_from_mother)*P(b_from_father)
P(bb) = 1*0.5
P(bb) = 0.5, so half of the children will have blue eyes
P(brown eyes) = P(BB) + P(Bb)
P(brown eyes) = P(B_from_mother)*P(B_from_father) + P(B_from_father)+P(b_from_mother)
P(brown eyes) = 0*0.5 + .5*1
P(brown eyes) = 0.5, so half the children will have brown eyes