The ball was 3 feet off the ground when she struck it with an initial upward velocity of 24 feet per sec. The equation I have to use is h=-16t^2+vt+h(sub zero)

Question

How do I graph this my x scale has to go by .25 so what is my y coordinates(h vs t)(h-x vs t-y) i also need to know what the equation for this problem would be

Answer 1

The equation is h = -16t² + 24t + 3 ; it's a quadratic equation

 

some pointers on how to graph this equation;

 

1) The graph is an inverted parabola

 

2) t is graphed on the x-axis; and h is graphed on the y-axis

 

3) It has a h intercept of +3

 

4) If you put h = 0, and solve the quadratic equation using the quadratic formula, you will get the curve cutting the t axis at t = 1.62, and - 0.116 seconds

 

5) If you take the limit of this function as t approaches + or - infinity, you will find on both occasions that h goes to negative infinity

 

6) using the completing of squares method or differential calculus, you get a maximum value of h as 12 ft and this occurs at t = 3/4 seconds; hence (3/4, 12) is a local maximum point.

 

With these six points you can plot the graph;

 

four points on the graph are (0, 3); ((1.62, 0); (-0.116, 0) and (0.75, 12), at which time both legs of the graph slopes towards negative infinity in the h direction.

 

Hope this helped you. If I had graphics on this software I would have been able to be more graphic with my explanation. If you have queries please feel free to message me.