Mark M. answered • 04/03/15
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Mathematics Teacher - NCLB Highly Qualified
log2(x - 1) - log2(x - 3) = log2(2x + 1) - log2(x - 3)
log2[(x - 1)/(x - 3)] = log2[(2x + 1)/(x - 3)]
(x - 1)/(x - 3) = (2x + 1)/(x - 3)
Solve for x.
Mark M.
"Cancelling" is not a proper term.
Since both the base, 2, and the exponents, logs, are equal, the bases must be equal.
If ax = bx, then a must be equal to b.
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04/03/15
Aaron C.
04/03/15