Jonathan F. answered • 09/30/12

Mathematics/writing tutor, with degrees in math and education

Feel free to submit any equation you need help with

Kathryn T.

asked • 09/30/12I am taking Calculus and having trouble with continuity and limits. Can I submit a problem I'm struggling with?

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Jonathan F. answered • 09/30/12

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New to Wyzant
Mathematics/writing tutor, with degrees in math and education

Feel free to submit any equation you need help with

Gaurav Y. answered • 10/08/21

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New to Wyzant
Hey, I am the best expert known

If you need help in questions with 100% accuracy

You can connect to me on whatsap number +919568314898 and send me the screenshots of the question.

Roy B. answered • 11/26/12

Tutor

4
(1)
Problem Solver - Math and Other Matters

hello:

i wonder if this has been answered. it's been posted a while back, i'm new to wyzant, and i don't see an answer yet. so, since i'm here, let's try this:

i believe the problem may be written this way:

lim { (1/h) *{ [ 1/(x+h)] - [1/x] } } as h→0

combining denominators:

lim { (1/h) *{ [ (x) - (x+h) ] / [ (x) * (x+h) ] } } as h→0

the x's on the numerator cancels and you're left with (-h) in the numerator, which yields:

lim { (1/h) *{ [ -h ] / [ (x) * (x+h) ] } } as h→0

the h in the numerator and the h in the denominator of the left-most term, i.e. (1/h) cancel, which yields:

lim { [-1] / [ (x) * (x+h) ] } as h→0

as h→0, the denominator becomes [ x^2 ]; thus the answer is:

[(-1) / (x^2)].

Bob A.

It seems to me that in the 1st equation the parentheses are different from the

problem as it was submitted, and so the order or operations has been changed.

{ (1/h) *{ [ 1/(x+h)] -
[1/x]
} } As in the solution

1/h [ (1/ x + h) -
(1/x)
] As in the submitted problem

Note there is an extra set of parens in the solution around the x+h in the second term.

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11/27/13

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Kathryn T.

for x is not equal to 0, what is the limit of 1/h[ (1/ x + h) - (1/x) ] when h approaches 009/30/12