The question is:

((x^2)-4)/ ((x-2)(x+3))

and then cancelling out the x-2 from both the denominator and the numerator leaving me with (x+2)/(X+3)? And then go from there to find the limit?

The question is:

((x^2)-4)/ ((x-2)(x+3))

and then cancelling out the x-2 from both the denominator and the numerator leaving me with (x+2)/(X+3)? And then go from there to find the limit?

Tutors, please sign in to answer this question.

Yes, you can simplify it that way, but then you need to note that your new Domain is all real numbers with the exception of 2.

Domain = R - {2} is how you would notate it.

Do you understand why? Do you know what makes two equations equilvent?

Danielle,

To echo/amplify Jon's point: you can of course cancel (x-2), but keep in mind there is a conditon for you to be able to do that: x-2 /= 0; or in other words, the cancellation is only valid for x /= 2.

Steven M.

Premium Test Prep and Subject Tutor - New York City UWS

New York, NY

5.0
(248 ratings)

Mary L.

K-12 Math tutor

New York, NY

5.0
(65 ratings)

John P.

Math, Science, Technology, and Test Prep Tutor

Fort Lee, NJ

5.0
(668 ratings)