IGNORE LAST ONE, I NEED THIS

Question

Suppose that Uranus rotates on its axis once every 17.2 hours. The equator lies on a circle with a diameter of 31,762 miles.

(a) Find the angular speed of a point on its equator in radians per day (24

 hours).

(b) Find the linear speed of a point on the equator in miles per day.

Do not round any intermediate computations, and round your answer to the nearest whole number.

Answer 1

(1 rev/17.2 hrs)(24hrs//1day)(2pi rad/1 rev) = 8.77 rad/day

v = radius times omega = (31762/2)8.77 = 139,300 miles/day

Answer 2

The angular speed is 2pi radians/17.2 hours

2pi/17.2 = x/24

24*2pi/17.2 = about 9 radians per 24 hour day.

Circumference is pi*d = 31762pi. The particle travels that distance in 17.2 hours.

31762pi/17.2 = x/24

24*31762pi/17.2 = x = about 139,232 miles per 24 hour day.