A car enters a highway at a speed of 5.8 meters/second and accelerates uniformly to 65 meters in 7.2 seconds. What is the speed of the car after this?

Answer 1

v(0) = 5.8

s(0)=0

s(7.2) = 65

s(t) =at^2/2 + vot

s(7.2) = a(7.2)^2 + 5.8(7.2) = 65

a = (65-41.76)/51.84

a= 23.24/51.84 = about 0.4483 m/sec/sec

v(t) = s'(t) = at +vo = at +5.8

v(7.2) = 0.4483(7.2) + 5.8

= 9.02777....

velocity in 7.2 seconds is about 9.03 meters per second