The shuttle lands on the runway at a speed of 105 meters/second. It then decelerates by parachute and comes to a complete stop in 60 seconds.

Question

Assuming constant acceleration, calculate the distance required for the shuttle to come to a complete stop.

Answer 1

v(0)=105

v(60)=0

v(t)=at +105

a=-105/60=-7/4

s(t)= -7t^2/8 +105t

s(60)= -7(60)^2/8 +105(60)

=-3150+6300

= 3150 meters