What is the oxidizing and reducing agent from this chemical reaction? And how many electrons did it gain (oxidizing) and lose(reducing)?

Question

H₂SO₄ + Ba(OH)₂ = BaSO₄ + H₂O

Answer 1

H₂SO₄ + Ba(OH)₂ = BaSO₄ + H₂O

S on the left has an oxidation number of 6+. On the right it has an oxidation number of 6+.

H is 1+ on both sides

Ba is 2+ on both sides

O is 2- on both sides.

This is NOT a redox reaction. Therefore there is no oxidizing or reducing agent.