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# Adding fractions by finding the LCD?

I can't seem to get past this problem...

2x   +     5

3x         x-8

For the answer I keep getting something like:  17x-13

3x(x-8)

Thanks for your help!

### 2 Answers by Expert Tutors

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Shannon M. | Biology Major Specializing in Science and MathBiology Major Specializing in Science an...
4.9 4.9 (83 lesson ratings) (83)
1

Once you find the LCD, which you have done correctly, you have to multiply the numerator and denominator of each by the same factor:

2x  (x-8)  +    5  (3x)

3x   (x-8)      x-8 (3x)

2x2 - 16x  + 8x   =  2x2 -8x    =   (x)(2x -4)    =  2x-4

(3x)(x-8)               3x2 - 24x       (x)(3x-24)        3x-24

### Comments

The end answer is not right on this. Sorry multiplication error. Should be 2x-1/3x-24

Asok B. | Ph. D in Biochemistry, willing to teach Chemistry, Biochemistry, MathPh. D in Biochemistry, willing to teach ...
4.7 4.7 (18 lesson ratings) (18)
0

your answer = {2x(x-8) + 15x}/3x(x-8)

= (2x2-16x+15x)/3x(x-8)

= (2x2-x)/3x(x-8)

=x(2x-1)/3x(x-8)

=2x-1/(3(x-8))