Adding fractions by finding the LCD?

Question

I can't seem to get past this problem...

  2x   +     5   

  3x         x-8

 

For the answer I keep getting something like:  17x-13

                                                                   3x(x-8)

 

Thanks for your help!

 

Answer 1

Once you find the LCD, which you have done correctly, you have to multiply the numerator and denominator of each by the same factor:

 2x  (x-8)  +    5  (3x)

 3x   (x-8)      x-8 (3x)

 

2x² - 16x  + 8x   =  2x² -8x    =   (x)(2x -4)    =  2x-4 

(3x)(x-8)               3x² - 24x       (x)(3x-24)        3x-24

Answer 2

 your answer = {2x(x-8) + 15x}/3x(x-8) 

= (2x²-16x+15x)/3x(x-8)

= (2x²-x)/3x(x-8)

=x(2x-1)/3x(x-8)

=2x-1/(3(x-8))