Inactive Tutor answered 08/25/21
for finding The magnitude |u×v| we will use |u×v| = |u| |v| sin ∅
∅ will be 45º in this situation because the northeast is in the middle of the north and east.
|u×v| = 10*6 sin 45º
= 60 sin45º
= 60*0.707
= 42.42
Dianz S.
asked 08/25/21You are looking down at a map. A vector u with |u| = 10 points north and a vector v with |v| = 6 points northeast. The crossproduct u×v points:
The magnitude |u×v| =
Inactive Tutor answered 08/25/21
for finding The magnitude |u×v| we will use |u×v| = |u| |v| sin ∅
∅ will be 45º in this situation because the northeast is in the middle of the north and east.
|u×v| = 10*6 sin 45º
= 60 sin45º
= 60*0.707
= 42.42
|| u × v || = || u|| ||v|| sin θ
The only piece left for you is to determine the angle θ
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