Roger N. answered 07/29/21
. BE in Civil Engineering . Senior Structural/Civil Engineer
the gravitational force assuming the same objects mass m1 = m2 = m and same distance is F1 = k (m1m2)/ r2 or
F1 = k (m2)/ r2 . If one of the objects is three times in mass than the other then m2 = 3m1 = 3m and if it moves 3 times the distance then r = 3r
substituting you get F2 = k( m1)(3m1)/ (3r)2 = k(m)(3m)/( 9r2) = k ( 3m2)/ 9r2 simplifying you get
F2 = k (m2) / 3 r2 , comparing this with original equation F1 = k (m2)/ r2 and F2 = k (m2) / 3 r2 divide F1 by F2 you get F1 / F2 = k (m2)/ r2 / k (m2) / 3 r2 simplifying , F1 / F2 = 3 and F2 = 1/3 F1 , therefore the force is reduced to 1/3 of the original force