Kam S.

# Given the vertices of a triangle PQR, P (3, -2, 7), Q (2, 2, -3) and R (1, 1, 2), define the coordinate of point S that will create a right isosceles triangle with right angle at P.

The hints given are: Use point Q as one of the corners. Point P will be the vertex/90 degree angle corner. The magnitude of PS and PQ should be perpendicular and have the same magnitude.

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I have my diagrams of this 3d plane-question but I am unsure of how to find coordinate S.