J.R. S. answered 06/01/21
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
1.575 L x 0.00250 mols / L x 106.45 g / mol = 0.419 g (ANSWER B)
Maddie D.
asked 06/01/21Sodium chlorate is used as an oxidizer in the manufacture of dyes, explosives and matches. Calculate the mass of solute needed to prepare 1.575 L of 0.00250 M NaClO3 (ℳ = 106.45 g/mol).
A. 419 g
B. 0.419 g
C. 0.169 g
D. 0.00394 g
E. 169 g
J.R. S. answered 06/01/21
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
1.575 L x 0.00250 mols / L x 106.45 g / mol = 0.419 g (ANSWER B)
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.