Maddie D.

asked • 06/01/21

please help me with honors chem molarity

Calculate each of the following quantities.

(a) grams of solute in 164.8 mL of 0.207 M calcium acetate

  ---------------g

(b) molarity of 584 mL solution containing 21.1 g of potassium iodide

 ----------------------M

(c) moles of solute in 145.6 L of 0.812 M sodium cyanide

----------------------------- mol


1 Expert Answer

By:

Maddie D.

it says that the last problem the 0.118 is wrong and off by multiple of ten
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06/02/21

Maddie D.

the last problem is wrong. I think it's a rounding issue. What would the correct answer be??? would it be 1.18???
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06/03/21

Maddie D.

1.18 is wrong too.
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06/03/21

J.R. S.

tutor
I'm sorry. I missed that is it 145.6 L (I read it as 145.6 ml). I'll go back and change it in the original answer. The answer would then be 145.6 L x 0.812 mol/L = 118.2 mols (off by a multiple of 1000, not 10)
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06/04/21

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