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Davinder S.

asked • 07/13/20

The angle θA = 35° above the x axis, and the angle θB = 59° below the x axis. 1)What is the magnitude of the car’s acceleration?

Car traveling on circular track. Point A is at positive x,y. Point B is at positive x, negative y.

A car is traveling around a horizontal circular track with radius r = 230 m as shown. It takes the car t = 52 s to go around the track once. The angle θA = 35° above the x axis, and the angle θB = 59° below the x axis.

1)What is the magnitude of the car’s acceleration?


2)What is the x component of the car’s velocity when it is at point A


3)What is the y component of the car’s velocity when it is at point A


4)What is the x component of the car’s acceleration when it is at point B


5)What is the y component of the car’s acceleration when it is at point B


6)

As the car passes point B, the y component of its velocity is(choose one)

increasing

constant

decreasing


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