For a submarine to stay submerged, it must be neutrally buoyant, which means it is maintaining a careful balance between its weight and the buoyant force of water pushing it toward the surface.

Question

If a submarine has an enclosed volume of 327.781 m3, how much must it weigh to stay submerged? (Use 1000 kg/m3 for the density of water.)

Answer 1

The buoyant force is given by the following equation:

F_B = ρgV

where ρ = density of the fluid, g = acceleration due to gravity, and V is the volume of displaced fluid. In this case, the volume of the displaced fluid would be the volume of the entire submarine and the density of the fluid is the density of water. Also, since the submarine is neutrally buoyant, this means that the buoyant force trying to push the submarine out of the water is equal to the weight of the submarine itself. I hope this helps!