J.R. S. answered 04/19/20
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
You are given initial pressure and volume and are asked to calculate a different pressure.
P1V1 = P2V2
(200 cm3)(1.00 atm) = (1.06 atm)(V2)
V2 = 189 cm3
J.R. S. answered 04/19/20
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
You are given initial pressure and volume and are asked to calculate a different pressure.
P1V1 = P2V2
(200 cm3)(1.00 atm) = (1.06 atm)(V2)
V2 = 189 cm3
Stanton D. answered 04/19/20
Tutor to Pique Your Sciences Interest
Hi Angel R.,
You would use the ideal gas law to consider your data:
pV = nRT
Since in the present case the value for n (number of moles of gas) didn't change, nor did the temperature, nor did R (it's a constant, it can't change, though its numeric value changes with the set of units used). So therefore, p and V are inversely related. So if you scale up the pressure from 1.00 atm to 1.06 atm (thereby squeezing it into a slightly smaller volume), that's a scale UP by 1.06 factor. So the volume will scale DOWN by a 1.06 factor (hint: try division).
-- Cheers, -- Mr. d.
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