According to the following balanced reaction, how many grams of NO are formed from 388 grams of NO2 if there is plenty of water present? 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g) (Please help Urgent)

Question

Formula: 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g)

Answer 1

3NO₂(g) + H₂O(l) ==> 2HNO₃(aq) + NO(g) ... balanced equation

Since H₂O is present in excess, we needn't worry about limiting reactant. The amount of NO produced will be dependent only on NO₂.

388 g NO₂ x 1 mol NO₂/46.0 g x 1 mol NO / 3 mol NO₂ x 30.0 g/mol NO = 84.3 g NO produced