A hunter shoots a 0.002 kg bullet at a deer 50 meters away. If the bullet accelerates at 2.5 x 105 m/sec2 and the mass of the gun is 2.5 kg, how many newtons of force is exerted on the bullet?

Answer 1

Applying Newton's second law F=m•a

so F = 0.002kg•2.5x10⁵m/s²

= 500kgm/s² = 500N

Hadassah J, if you need further clarification, please let me know.

Mr A