
Patrick B. answered 10/13/19
Math and computer tutor/teacher
1) 5x (x^2 + 2x + 1) = 0
5x ( x + 1)(x+1) = 0
x=0, x=-1 , x=-1
2) x^2 (x+2) -9(x+2) = 0
(x+2)(x^2 - 9) = 0
(x+2)(x+3)(x-3) = 0
x=-2, x=-3 , x=3
Lily G.
asked 10/13/19Solve each polynomial equation by factoring:
Patrick B. answered 10/13/19
Math and computer tutor/teacher
1) 5x (x^2 + 2x + 1) = 0
5x ( x + 1)(x+1) = 0
x=0, x=-1 , x=-1
2) x^2 (x+2) -9(x+2) = 0
(x+2)(x^2 - 9) = 0
(x+2)(x+3)(x-3) = 0
x=-2, x=-3 , x=3
1) Factor out 5x since all of the monomials [single terms] have a common factor of 5x
5x (x^2 + 2x + 1) = 0
Factor out the remaining polynomial- x^2 + 2x + 1
5x ( x + 1)(x+1) = 0
Set them all equal to zero and solve for x
x=0, x=-1 , x=-1
2) The first two monomials and the last two monomials both share the binomial x+2 in common, so factor that out
x^2 (x+2) -9(x+2) = 0
Then combine x^2 and -9 into one binomial and keep x+2 as the other binomial
(x+2)(x^2 - 9) = 0
Factor out x^2 and -9
(x+2)(x+3)(x-3) = 0
Set them all equal to 0 and solve for x
x=-2, x=-3 , x=3
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