the perimeter of a rectangular field is 374 yd. The length of the field is 5 yards less than triple the width. what are the dimensions of the playing field

Answer 1

Let w= width then Length= 3w-5

Perimeter = 2(w) +2(3w-5) =374

374 = 2w + 6w -10

384 = 8w

w= 48

l = 3(48) -5 = 139

width =48 and length=139

Answer 2

This is a question that tests our understanding of perimeter formula and ability to draw equations out of this word problem. We know the perimeter is the sum of all the sides, length+length+width+width, or 2*length+2*width, and in this case that is 374. We also know that the length of this rectangle is 5 less than 3 times the width. So length = 3 * width - 5. Now we have two equations and two variables:

2l+2w=374

l=3w-5

With 2 equations and 2 variables, we can solve by substituting 3w-5 in for l in the first equation to get:

2(3w-5)+2w=374

6w-10+2w=374

8w=384

w=48

width = 48, and so length would be 3*48-5=139. Doublechecking, 48+48+139+139=374, so our rectangular playing field is 48x139