Lara S.

asked • 02/17/19

how do i deduce the moles of the acid reacted with sodium carbonate

The balanced equation is: Na2CO3 + 2HCl ----> 2NaCl + H2O + CO2

Moles of sodium carbonate: 0.03945

average volume of acid added: 26.3 cm3

Acid = HCl

This is standardisation of an acid (titration 1)

1 Expert Answer


Lara S.

how do I find the concentration of HCl used


J.R. S.

I included that calculation at the end of my discussion. The concentration of the HCl is 3 M or 3 moles/liter.


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