J.R. S. answered 01/29/19
Ph.D. University Professor with 10+ years Tutoring Experience
Write a balanced equation for the reaction taking place:
2LiOH + CO2 ==> Li2CO3 + H2O
Now use the molar ratios (stoichiometry) of the balanced equation to find moles of CO2 absorbed then convert this to grams of CO2 absorbed:
moles of LiOH present = 1 g LiOH x 1 mole LiOH/23.95 g = 0.0418 moles LiOH
moles of CO2 that can be absorbed = 0.0418 moles LiOH x 1 mole CO2/2 moles LiOH = 0.0209 moles CO2
mass of CO2 that can be absorbed = 0.0209 moles CO2 x 44 g/mole = 0.9 g CO2 (to 1 sig. fig.)