I am lost, please help me.

Question

A chemist has 4 L of a solution that contains 0.36 L of acetic acid. The chemist needs to prepare 6 L of a solution with the same percent concentration of acetic acid. How much acidic acid must the 6 L of the solution contain?

Answer 1

Well, there are a couple of ways you could answer this question. An easy way would be to set up a proportion. Let the unknown be x. So, .36L is to 4L as x is to 6L.

 

.36/4 =x/6

cross multiply

4x = 2.16

divide by 4

x = 0.54L

Answer 2

This is basically a proportionality question the equation for this is as follows....

 

(Volume of acid)₁ / (Total Volume)₁ = (Volume of acid)₂ / (Total Volume)₂

 

so we get...

 

(0.36)/ (4) = x / (6)

 

x = (0.36) x (6) / (4)

 

x = 0.54 L of acetic Acid