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Using x and y for the two dimensions gives us an equation for the area of xy = A
We have 300 feet of fence to work with, so 3x + 2y = 300.
We want to maximize the area function, but we can't graph it or take its derivative while it has three variables.
(Depending on whether this is a calculus problem or an algebra II problem)
Solve the linear equation for y to get y = (300 - 3x)/2
Plug this expression for y into the area equation to get
x(300 - 3x)/2 = A
Put this quadratic in standard form by distributing the x and dividing by 2
--(3/2)x2 + 150x = A
Now you can graph it and find the highest point on the graph (in algebra), or take the derivative and set it equal to 0 (in calculus to identify the max)
Let me know if you have further questions.