Alain G.

asked • 12/15/13

How to solve for x

6^x=0.25^2x-1
 
x/2x-1=log(0.25)/log(6) 
 
I've got so far.

William S.

Alain,
 
Am I supposed to interpret this as
 
6x = 0.25x - 1
 
or
 
6x = 0.25(x-1)
 
It makes a big difference!
Report

12/15/13

Alain G.

The second one in brackets.
0.25^(x-1)
Report

12/15/13

2 Answers By Expert Tutors

By:

Charles D. answered • 12/16/13

Patient and Knowledgeable Tutoring by Charles

William S. answered • 12/15/13

Experienced scientist, mathematician and instructor - William

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