^{2}-7x

f(x) = 8x^{2} -7x

g(x) = 8x - 4

(fog)(x)

I would really appreciate the steps and final outcome of this problem. Thank you!

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I'm sorry, Kateln, I'm sort of in the fog on this one. I'm not sure what (fog)(x) means, but I'm going to interpret if as f[g(x)]

f of g of x

f[g(x)] = 8*[g(x)]^{2} - 7*{g(x)]

= 8*(8x - 4)^{2} - 7*(8x - 4)

= 512x^{2} -512x + 128 - (56x - 28)

= 512x^{2} - x(512 + 56) + 156

= 512x^{2} - 568x + 156

I hope I've interpreted the problem correctly.

f(x)=8x^2-7x

g(x)=8x-4

f(g(x))=f(8x-4)=8(8x-4)^2-7(8x-4)

=8(64x^2-64x+16)-56x+28

=512x^2-512x+128-56x+28

=512x^2-568x+156

Michael F. | Mathematics TutorMathematics Tutor

f(x)=8x^{2}-7x g(x)=8x-4

(fog)(x)=f(g(x))=8(g(x)^{2})-7g(x)=8(8x-4)^{2}-7(8x-4)=8(64x^{2}-64x+16)-56x+28=512x^{2}-512x+128-56x+28

=512x^{2}-568x+156

f(x) = 8x

g(x) =

(f o g)(x) = f[

8(8x - 4)

8(64x

512x

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## Comments

(128x^2 - 142x + 39)4