f(x) = 8x

^{2}-7xg(x) = 8x - 4

(fog)(x)

I would really appreciate the steps and final outcome of this problem. Thank you!

f(x) = 8x^{2} -7x

g(x) = 8x - 4

(fog)(x)

I would really appreciate the steps and final outcome of this problem. Thank you!

Tutors, please sign in to answer this question.

Hallandale, FL

f(x) = 8x

g(x) =

(f o g)(x) = f[

8(8x - 4)

8(64x

512x

Westford, MA

N.B. Understanding composition of functions is fundamental to understanding and using the chain rule of differentiation in calculus.

Aliquippa, PA

I'm sorry, Kateln, I'm sort of in the fog on this one. I'm not sure what (fog)(x) means, but I'm going to interpret if as f[g(x)]

f of g of x

f[g(x)] = 8*[g(x)]^{2} - 7*{g(x)]

= 8*(8x - 4)^{2} - 7*(8x - 4)

= 512x^{2} -512x + 128 - (56x - 28)

= 512x^{2} - x(512 + 56) + 156

= 512x^{2} - 568x + 156

I hope I've interpreted the problem correctly.

Saugus, MA

f(x)=8x^2-7x

g(x)=8x-4

f(g(x))=f(8x-4)=8(8x-4)^2-7(8x-4)

=8(64x^2-64x+16)-56x+28

=512x^2-512x+128-56x+28

=512x^2-568x+156

Wilton, CT

f(x)=8x^{2}-7x g(x)=8x-4

(fog)(x)=f(g(x))=8(g(x)^{2})-7g(x)=8(8x-4)^{2}-7(8x-4)=8(64x^{2}-64x+16)-56x+28=512x^{2}-512x+128-56x+28

=512x^{2}-568x+156

- Algebra 2 3503
- Algebra 5059
- Math 9863
- Prealgebra 172
- Algebra Word Problem 2488
- Algebra Help 967
- Geometry 1907
- Math Help 5447
- Word Problem 5121
- Precalculus 1586

## Comments

(128x^2 - 142x + 39)4