f(x) = 8x

^{2}-7xg(x) = 8x - 4

(fog)(x)

I would really appreciate the steps and final outcome of this problem. Thank you!

f(x) = 8x^{2} -7x

g(x) = 8x - 4

(fog)(x)

I would really appreciate the steps and final outcome of this problem. Thank you!

Tutors, please sign in to answer this question.

Hallandale, FL

f(x) = 8x

g(x) =

(f o g)(x) = f[

8(8x - 4)

8(64x

512x

Westford, MA

N.B. Understanding composition of functions is fundamental to understanding and using the chain rule of differentiation in calculus.

Aliquippa, PA

I'm sorry, Kateln, I'm sort of in the fog on this one. I'm not sure what (fog)(x) means, but I'm going to interpret if as f[g(x)]

f of g of x

f[g(x)] = 8*[g(x)]^{2} - 7*{g(x)]

= 8*(8x - 4)^{2} - 7*(8x - 4)

= 512x^{2} -512x + 128 - (56x - 28)

= 512x^{2} - x(512 + 56) + 156

= 512x^{2} - 568x + 156

I hope I've interpreted the problem correctly.

Saugus, MA

f(x)=8x^2-7x

g(x)=8x-4

f(g(x))=f(8x-4)=8(8x-4)^2-7(8x-4)

=8(64x^2-64x+16)-56x+28

=512x^2-512x+128-56x+28

=512x^2-568x+156

Wilton, CT

f(x)=8x^{2}-7x g(x)=8x-4

(fog)(x)=f(g(x))=8(g(x)^{2})-7g(x)=8(8x-4)^{2}-7(8x-4)=8(64x^{2}-64x+16)-56x+28=512x^{2}-512x+128-56x+28

=512x^{2}-568x+156

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## Comments

(128x^2 - 142x + 39)4