
David W. answered 03/12/16
Tutor
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Experienced Prof
The Standard Form of the equation of a line looks like: Ax + By = C
By convention, the "A" positive, so you may have to multiply by (-1) to make that happen.
The slope-intercept form of the equation of a line looks like: y= mx + b
where m is the slope and b is the y-intercept
The point-slope form of the equation of a line looks like:
(y - y1) = m (x - x1) where m is the slope (y2- y1) / (x2 - x1)
Slope, m, is sometimes called "rise" over "run" because it is the increase in the y-values divided by the increase in the x-values. Note that a positive slope means that the line slants upward to the right and a negative slope means that the line slants downward to the right.
Putting this together, the point-slope form is:
(y - y1) = ( (y2 - y1) / (x2 - x1) ) (x - x1)
The problem gives the point (1,1) and a slope, m=(-3)
In point-slope form, that is:
(y - 1) = (-3)(x - 1)
To get that equation into Standard Form (see above):
(y - 1) = (-3)(x - 1)
y - 1 = -3x + 1 [distribute]
y = -3x + 4 [add 1 to both sides]
3x + y = 4 [add 3x to both sides; Standard Form]
Your example:
y-3 = 3(x+1) [point (-1,3) with slope of 3]
y - 3 = 3x + 3 [distribute]
y = 3x + 6 [add 3 to both sides]
-3x + y = 6 [subtract 3x from both sides]
3x - y = -6 [multiply by (-1) to make 3x positive]
Nicole V.
03/12/16