15 Answered Questions for the topic Center
05/02/17
(x+1)^2/9 -(y-3)^2/16 =1
(x+1)2 - (y-3)2 =1
9. 16.
Find the center , foci,vertices, and asymptotes of the hyperbola
02/15/16
equation of the circle
Put the equation of the circle in standard form, identify the center (h,k) radius r of the circle.
x2+y2-2x-12y+28=0
05/27/15
Identify the type of conic section and coordinates of the center, foci and vertices.
(y+3)^2/25+(x-2)^2/16=1
08/20/14
3x^2-12y^2+6x+48y-93=0
Given the equation: 3x^2-12y^2+6x+48y-93=0 determine:
a: The center C
b: the two vertices
c: the slopes of the asymptotes
A hyperbola is centered at C=(3,7). The vertices are (9,7) and (-3,7). The slopes of the asymptotes are m=+-5/6
A hyperbola is centered at C=(3,7). The vertices are (9,7) and (-3,7). The slopes of the asymptotes are m=+-5/6.
08/18/14
(x+7)^2+(y-6)^2=1
If the major axis is horizontal and has a length of 22 units, the minor axis has a length of 18, and the ellipse has a center (-7,6) fill in the missing denominators for the equation and determine...
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(x-4)^2/49+(y+5)^2/16=1
Given the equation: (x-4)^2/49+(y+5)^2/16=1 find:
a: The Center C
b: Length of Major Axis
c: Length of Minor Axis
d: Distance from C to Foci c
08/18/14
(x-4)^2+(y+2)^2=1
Given the equation: (x-4)^2+(y+2)^2=1 find:
a: The Center C
b: Length of Major Axis
c: Length of Minor Axis
d: Distance from C to foci c
08/18/14
(x+5)^2/25+y^2/64=1
Given the equation: (x+5)^2/25+y^2/64=1 find:
a: The Center C
b: Length of Major Axis
c: Length of Minor Axis
d: Distance from C to foci c
points help show work
Consider the points (4,-7) and (-6, 13).
(a) Find the midpoint. Show work.
(b) If the point you found in (a) is the center of a circle, and the other two points are points on the circle, find the...
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03/31/14
center and radius
State the center and the radius of the circle represented by the equation. show all work
(x-4)^2+(y+6)^2=64
11/21/13
equation of a circle
write the equation of the circle x2+y2-6x+8y=0 in the standard form. Find the radius of the circle and the distance from the center to the origin
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