(x-4)^2/49+(y+5)^2/16=1

Question

Given the equation: (x-4)^2/49+(y+5)^2/16=1 find:

a: The Center C

b: Length of Major Axis

c: Length of Minor Axis

d: Distance from C to Foci c

Answer 1

you can answer the question from these values

 

h = 4, k = -5, a = 7, b = 4