(x-4)^2+(y+2)^2=1

Question

Given the equation: (x-4)^2+(y+2)^2=1 find:

a: The Center C

b: Length of Major Axis

c: Length of Minor Axis

d: Distance from C to foci c

Answer 1

in this example a = b = 1, therefore this is an equation for a circle, not an ellipse.

the center is still (h , k) but the major and minor axes are the diameter of the circle and of course are equal length.

In this case, the radius = 1 so the diameter is 2

 

The focus and the center are one and the same because c = 0.